Discover the starting grid for the Singapore GP

No, you're not dreaming: the starting grid looks exactly like the qualifying rankings. This is quite simply because the race direction did not impose any penalties! Enough to obtain a sportingly fair order and certainly a regular race.

Lewis Hamilton (Mercedes) will start from pole after having signed a remarkable lap in Q3. As in 2017, Max Verstappen (Red Bull) achieved the second best time.

Bright lights, big city…one mega lap!

Take it away, Lewis #SingaporeGP #F1 pic.twitter.com/yqf6x9KRMN

— Formula 1 (@F1) September 15, 2018

Historically very comfortable on this track (four victories), Sebastian Vettel (Ferrari) will have work to do if he is to catch Lewis Hamilton from his third place.

The battle for fourth position in the Manufacturers' standings will be close, as is often the case. Sergio Pérez (Racing Point Force India) holds the advantage but will start on the same line as Romain Grosjean (Haas). The latter will be keen to make people forget his exclusion from the Italian GP.

Esteban Ocon (Racing Pont Force India) sees top 10 points as do drivers Renault : Nico Hulkenberg will start 10th, Carlos Sainz Jr 12th. Pierre Gasly (Toro Rosso) will have more difficulty with 15th position.

The Singapore Grand Prix will start at 14:10 p.m. and can be followed on our site with live streaming.ext.

Starting grid for the 2018 Singapore Grand Prix:

1. Lewis Hamilton (Mercedes) – 2. Max Verstappen (Red Bull)

3. Sebastian Vettel (Ferrari) – 4. Valtteri Bottas (Mercedes)

5. Kimi Räikkönen (Ferrari) – 6. Daniel Ricciardo (Redbull)

7. Sergio Pérez (Racing Point Force India) – 8. Romain Grosjean (Haas)

9. Esteban Ocon (Racing Point Force India) – 10. Nico Hülkenberg (Renault)

11. Fernando Alonso (McLaren) – 12. Carlos Sainz Jr (Renault)

13. Charles Leclerc (Sauber) – 14. Marcus Ericsson (Sauber)

15. Pierre Gasly (Toro Rosso) – 16. Kevin Magnussen (Haas)

17. Brendon Hartley (Toro Rosso) – 18. Stoffel Vandoorne (McLaren)

19. Sergey Siroktin (Williams) - 20. Lance stroll (Williams)