IndyCar – Will Power steals pole from Simon Pagenaud

The first starting grid of the year in IndyCar will be dominated by the DW12 / Chevrolet of Team Penske, author of a quadruplet this Saturday. The Australian Will Power, reigning champion, was the fastest on the Florida track of St Petersburg to take the first pole position of the season. Author of a best lap in 1'00″693, Power is only three hundredths ahead of his new teammate, the Frenchman. simon pagenaud. The two men are followed by the Brazilian Helio Castroneves and the Colombian Juan-Pablo Montoya, who also defend the colors of “The Captain” team.

The Japanese Takuma Sato (AJ Foyt Enterprises), pole winner last year on this same circuit, ranks 5th and first Honda. It precedes the car from Sarthois Sébastien Bourdais (KV Racing), which also makes a nice introduction. The first DW12 from Ganassi, that of the Brazilian Tony Kanaan, will start from 7th position in front of the American Ryan Hunter-Reay, first representative of Andretti Autosport.